2x^4-x^2=15

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Solution for 2x^4-x^2=15 equation:


Simplifying
2x4 + -1x2 = 15

Reorder the terms:
-1x2 + 2x4 = 15

Solving
-1x2 + 2x4 = 15

Solving for variable 'x'.

Reorder the terms:
-15 + -1x2 + 2x4 = 15 + -15

Combine like terms: 15 + -15 = 0
-15 + -1x2 + 2x4 = 0

Factor a trinomial.
(-5 + -2x2)(3 + -1x2) = 0

Subproblem 1

Set the factor '(-5 + -2x2)' equal to zero and attempt to solve: Simplifying -5 + -2x2 = 0 Solving -5 + -2x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -2x2 = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -2x2 = 0 + 5 -2x2 = 0 + 5 Combine like terms: 0 + 5 = 5 -2x2 = 5 Divide each side by '-2'. x2 = -2.5 Simplifying x2 = -2.5 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(3 + -1x2)' equal to zero and attempt to solve: Simplifying 3 + -1x2 = 0 Solving 3 + -1x2 = 0 Move all terms containing x to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1x2 = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1x2 = 0 + -3 -1x2 = 0 + -3 Combine like terms: 0 + -3 = -3 -1x2 = -3 Divide each side by '-1'. x2 = 3 Simplifying x2 = 3 Take the square root of each side: x = {-1.732050808, 1.732050808}

Solution

x = {-1.732050808, 1.732050808}

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